9|x + 3| -2 > 43
2007-09-09 04:18:41 · 9 answers · asked by brooklynchyck808 3 in Science & Mathematics ➔ Mathematics
9|x + 3| -2 > 43
9x + 27 -2 > 43
9x + 25 > 43
9x > 43 - 25
9x > 18
9x/9 > 18/9
x > 2
2007-09-09 04:23:40 · answer #1 · answered by Runa 7 · 0⤊ 0⤋
9(x+3)-2= 43
9x+27-2= 43
9x+25= 43
9x= 43-25
9x=18
x=18/9
x=2 Ans.
2007-09-09 11:52:08 · answer #2 · answered by Anonymous · 0⤊ 0⤋
9|x + 3| -2 > 43
add 2 to both sides:
9 | x+3 | > 45
divide both sides by 9:
| x+3 | > 5
equation can be restated as:
-5 > x+3 > 5
subtracting 3 from both sides to simplify:
-8 > x > 2
2007-09-13 02:25:54 · answer #3 · answered by Pakyuol 7 · 0⤊ 0⤋
9|x + 3| -2 > 43
9|x + 3| > 45
|x + 3| > 5
therefore,
x + 3 > 5 or x + 3 < -5
x > 2 or x < -8
2007-09-09 11:27:18 · answer #4 · answered by Aaron 2 · 0⤊ 0⤋
9|x + 3| - 2 > 43
9|x + 3| > 45
|x + 3| >5
If the quantity (x + 3) is positive this statement means:
x + 3 > 5
x > 2
If the quantity (x + 3) is negative this statement means:
-(x + 3) > 5
x + 3 < -5
x < -8
So the correct answer is:
x > 2 or x < -8
2007-09-09 11:34:56 · answer #5 · answered by jsardi56 7 · 0⤊ 0⤋
9|x + 3| -2 > 43
9|x + 3| > 45
9x + 27 > 45
x > 2
OR
-9x -27 > 45
x < -8
2007-09-09 11:30:00 · answer #6 · answered by Bananaman 5 · 0⤊ 0⤋
9Ix+3I-2>43
9Ix+3I>45
Ix+3I>5
x+3>5 , x+3<-5
if x+3>5, x>2
if x+3 <-5, x<-8
2007-09-09 11:26:41 · answer #7 · answered by irfank58 1 · 0⤊ 0⤋
the x+3 is an absolute value, which means that it could be x+3 or x-3
2007-09-09 11:24:42 · answer #8 · answered by Chris 3 · 0⤊ 1⤋
x will be any number more than 2.it can be 3,4,5,6,etc
2007-09-09 11:23:50 · answer #9 · answered by aman d 2 · 1⤊ 0⤋