English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

When an object falls through air, there's a drag force (with dimension M * L/T^2) that depends on the product of the surface area of the object and the square of its velocity; i.e.,

F = C A v^2

where C is a constant.
The constant C has dimensions of _____

2007-09-09 03:05:54 · 2 answers · asked by MD12 2 in Science & Mathematics Physics

well that's not one of the choices out of 10 different ones lol so thanks but try again

2007-09-09 03:31:23 · update #1

2 answers

the answer is M*L
so we get
M*L*L^(-2) *L^2/T^2=M*L/T^2

2007-09-09 03:25:44 · answer #1 · answered by Peter Lustmolch 2 · 0 1

For the purpose of this discussion lets use K for kilograms.
The units of force are newtons or Km/s^2
A (area) must be squared linear units, say square meters.
And v is m/s.
F = C Av^2
C = F/Av^2
As far as units go that's :
[....] = (Km/s^2)/((m^2)(m/s)^2) =
(Km/s^)/(m^4/s^2) =
(Km/s^2)(s^2/m^4) =
K/m^3

2007-09-09 13:38:58 · answer #2 · answered by jsardi56 7 · 0 0

fedest.com, questions and answers