Find the slope of a line perpendicular to the one that that passes through (-9,19) and (12,-3)?

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Find the slope of a line perpendicular to the one that that passes through (-9,19) and (12,-3)?

2007-09-09 02:09:41 · 3 answers · asked by daniel c 1 in Science & Mathematics ➔ Mathematics

3 answers

m1 = - 22 / 21
m2 is slope of perpendicular
(m1) (m2) = - 1
( - 22 / 21 )( m2 ) = - 1
m2 = 21 / 22

2007-09-12 22:15:56 · answer #1 · answered by Como 7 · 0⤊ 0⤋

m = -3 - 19/12-(-9)
=-22/21

2007-09-09 02:29:43 · answer #2 · answered by Anonymous · 0⤊ 0⤋

ammm.. wait...

(y-y1)/(x-x1)
(19+3)/(-9-12)
22/-21

= -22/21...

then....

y-y1=m(x-x1)
y-19 = -22/21(x+9)
-21y+399 = 22x + 198
22x+21y-201=0...

that's my answer...

2007-09-09 02:17:55 · answer #3 · answered by Jocel B. Bartolay 2 · 0⤊ 0⤋