f(x)= x^4 on the interval [3,9]
2007-09-07 20:47:47 · 5 answers · asked by biomes 1 in Science & Mathematics ➔ Mathematics
area = ∫x^4 dx, x from 3 to 9
2007-09-07 20:54:03 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
The area of a region under a graph is calculated using 'integration', thus if f(x) = x^4, the function becomes
F(x) = (1/5)x^5
F(x) is the expression of the area
(I want to write this down with the right symbols, however, not possible)
If you want to calculate the area on the interval [3, 9], it is simply F(9) - F(3) = (1/5)9^5 - (1/5)3^5 = 59049/5 - 243/5 = 58806 / 5 = 11761.2
2007-09-08 03:59:27 · answer #2 · answered by Anonymous · 0⤊ 0⤋
A = â« x^4 dx between 3 and 9
A = x^5 / 5 between 3 and 9
A = 9^5 / 5 - 3^5 / 5
A = 11761 units ² (to nearest whole number)
2007-09-12 02:37:08 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Definite integral of x^4dx in the interval.
2007-09-08 03:57:52 · answer #4 · answered by cattbarf 7 · 1⤊ 0⤋
why dont you do your own homework instead of expecting us to do it for you
2007-09-08 03:54:30 · answer #5 · answered by IT'S ME AGAIN 6 · 2⤊ 0⤋