Physics Problem. U gotta help me. PLS??????

Question

If 1kg of ice at 0C is mixed with 1kg of water at 10C. Then wat will be the resulting temperature?

Pls tell the answer with the Reason

Answer 1

The energy stored in ice is related to the transition from water to ice. The process requires energy which is approximately 80,000 calories per liter. Boiling water also has a transition from water to steam but the value per liter is 540,000 calories. For one liter of boiling water compared to one liter of ice, the energy stored in the steam is nearly 7
times more per liter. An iceberg is huge compared to a cup of water, thus the energy stored is much greater.

First order transition - a thermal transition that involves both a latent heat and a change in the heat capacity of the material. (see: heat capacity, latent heat, second order transition, thermal transition)
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Answer 2

To melt the ice requires 334.16 J per gram:

1 kg = 1000 g
Energy to melt all the ice = 3.34x10^5 J

This energy must come from the 1kg of water at 10C
The specific heat of water is 4.186 J per gram. The water is at 10C so:
Excess heat above 0: 1000*4.186*10 = 4.186x10^4 J

So the water will cool down to 0 and some of the ice will melt but the final temperature will be 0 since there is not enough heat in the water to melt all the ice and then raise the temperature above 0.

Answer 3

As the ice melts, it has to absorb (you look up the numbers in your Physics book) some number of calories per gram to become liquid (this is called the 'latent heat of fusion'). When liquid water 'gives up' energy, it's temperature drops by some number of degres per gram for every calorie it gives to the ice.

Figure out how many calories it will take to move 1 kg of ice through its laten heat requirement and then figure how many degrees the water will have to lose.

Now go do your homework ☺

Doug

Answer 4

♠ still zero! To melt 1kg of ice you must add 3.35·10^5 Joules;
♣ to cool 1kg of water you must take away 10*4180=0.4·10^5 Joules;
compare!

Answer 5

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