Help w/ Electric Field Physics. Easy Points!!!!?

Question

The figure shows an electric dipole. What is the direction (relative to the positive direction of the x axis) of the dipole's electric field at point P, located at distance r >> d?

in other words, positive i-hat direction? positive j-hat?? etc

http://www.s89.photobucket.com/albums/k239/blueray4/?action=view¤t=hrw7_22-38.gif

Answer 1

I dont know how to answer this mathmatically, but from building dipole antennas since the 60's ... It radiates from a +p to -P with r as the center.. In a curve with most of the radiation centered at r... There is little or no radiation on the ends...

Answer 2

The electric field always points in the direction a positive test charge will travel when released from rest at a given point.

In order to find the electric field vector at point P, you must find the resultant vector formed by the component vectors from each point change individually.

Formula for Electric Field: E = k*q / r^2

The shortcut to this problem is that by symmetry that point P is equal distance from both charges, and that the charges are equal polar opposites, the 'x' (i-hat) component vectors from each of the charges will cancel out. Thus leaves the 'y' (j-hat) component vectors to sum to the resultant electric field vector. In this case, the electric field at point P will be twice the 'y' (j-hat) component vector of either point charge.

Now all that's left is to figure out the location of the point P as 'r' increases. Electric field will approach zero as 'r' approaches infinity. So as 'r' reaches zero, the electric field will be at a peak maximum.

In this problem the direction of the resultant electric field caused by the dipole charges will be in the negative 'y' (j-hat) direction as long as the point P remains equal distance between the two point charges.

Answer 3

♥ looking for simpletons who’d believe you? switch on your own stripe-carrier sometimes!

Answer 4

to the right I suppose