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1.a line of plane contains the points(-3,2)and (4,1)
a.find the slope of the line
b.find an equation for the line
c.find an equation of a line that contains(7,5)and it is parallel to the line above
d.find an equation of a line that contains(7,5)and is perpendicular to the line above
e.find the coordinates of the midpoint and the lengt of the segment determined by(-3,2)and (4,1)

2.find zeros of each function below.graph the functions
a. 3(x-2)=y
b. 4x + 6y=18
c. y=2x(SQUARED)- 2
D. Y=-3X(SQUARED) + 12
THANK YOU!!!!!

2007-09-07 16:46:48 · 7 answers · asked by witch_dea 2 in Science & Mathematics Mathematics

7 answers

1)
a. slope = (y2- y1)/(x2-x1) = (1 - 2)/ 4 - (-3) = 1/7

b. y=(1/7)x + b
at (4,1)
b= 1 - (1/7)4 = 1- 4/7 = 3 /7
==> y=(1/7)x + 3/7

c. parallel ==> same slope
y=(1/7)x + b
at(7,5)
b= 5 - (1/7)7 = 4
==> y=(1/7)x + 4

d. 2 lines are perpendicular if product of their slopes is -1
==> (1/7)*a = -1
==> a= -7
==> y=-7x + b
at (7,5)
b= 5 +7*7 = 54
==> y= -7x + 54

e. x= (x1+x2)/2= (-3 + 4)/ 2 = 1/2
y=(y1 + y2)/2 = (2+1)/2 = 3/2
==> (1/2, 3/2)


xd=x1-x2 = -3 - 4 = -7
yd=2 - 1= 1
length= sqrt(xdxd^2 + yd^2) = sqrt((-7)^2 + 1^2) = sqrt(49 +1)
=sqrt(50) ~= 7.07

2) y=0
a. 3(x-2) = 0
3x - 6 = 0
x= 6/3 = 2

b. 4x + 6(0) = 18
4x=18
x=18/4
x=4.5

c. 0 = 2x^2 - 2
2x^2 = 2
x^2 = 1
x= 1 or x = -1

d. 0 = -3x^2 + 12
3x^2 = 12
x^2 = 12/3
x^2 = 4
x= 2 or x= -2

2007-09-07 17:16:16 · answer #1 · answered by aspx 4 · 0 0

1a. The slope is change in y over change in x, so the slope of the line containing points (x1, y1) and (x2, y2) is (y2 - y1) / (x2 - x1).

b. Remember the general equation for a line is y = mx + b. You found m, the slope in part "a". Now plug in a point and solve for b. That gives you b. Now that you know both m and b, you can write the equation.

c. Parallel lines have the same slope. Use that point and the same process in part b.

d. Perpendicular lines have slopes that are negative reciprocals of each other. So change m to -1/m, and use the given point to find b.

e. Use the midpoint formula ( [x2 + x1]/2, [y2 + y1]/2)

2. Set y equal to 0 and solve for x.

2007-09-07 17:25:06 · answer #2 · answered by Anonymous · 0 0

1.b

find your slope and pick a point on the line to sub into
y = mx+b where m = the slope

then solve for b

once you solve for b, insert it back into y = mx+b for the equation of the line.

2007-09-07 17:00:32 · answer #3 · answered by (+_+) B 4 · 0 0

1A.
slope = rise / run
slope = (2 - 1) / (-3 - 4)
slope = 1 / -7

2007-09-07 16:54:44 · answer #4 · answered by Anonymous · 0 0

Man, we work for points, and the points we get for all this dogwork isn't worth it. Break your problems in half and submit each half as a separate question. Also, do your own homework.

2007-09-07 16:54:29 · answer #5 · answered by cattbarf 7 · 4 0

I'm not going to do your homework for you for free. Ask a teacher.

2007-09-07 16:57:39 · answer #6 · answered by fooles.troupe 7 · 0 0

try Dr. Math.com.................I want you to learn because giving you straight answers is not the correct thing to do....and I am not very good at explaining problems.

2007-09-07 16:55:42 · answer #7 · answered by Anonymous · 1 2

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