A particle moving along the x axis is located at 13.3 m at 1.77 s and at 4.25 m at 3.47 s. Find its displacement during this time interval? (answer in m)
2007-09-07 16:20:36 · 5 answers · asked by Cnall 1 in Science & Mathematics ➔ Physics
Distance travelled = 4.25 -13.3 = 9.05m
Time taken.............= 3.47 - 1.77= 1.7s
The displacement in 1.7 s= -9.05m
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2007-09-07 17:49:22 · answer #1 · answered by Joymash 6 · 0⤊ 0⤋
The particle moving along the x-axis, consisted with the speed of light ( 3 x 10 exp 8 m/s) the displacement- time formula with the speed of light.... and then subtract the two variables displacement x1 and displacement x2... the RESULT Displacement is the ANSWER.......
2007-09-07 17:02:25 · answer #2 · answered by MARIL 1 · 0⤊ 0⤋
Take the final location and subtract the initial location from it. If the answer is negative (as it will be here), the displacement is to the left.
2007-09-07 16:44:56 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
At 1.7 seconds (time interval) b/w 1.77 s - 3.47 s, its displacement = 9.05 m
2007-09-07 16:46:11 · answer #4 · answered by arnie 3 · 0⤊ 0⤋
The displacement is 13.3 - 4.25
which is 9.05 m
2007-09-07 17:48:02 · answer #5 · answered by halrosser 5 · 0⤊ 0⤋