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can anyone solve this for me for X
for me all these numbers and pi are so intimidating...
and i keep gettin a huge number and that just does no seem right to me...
SOMEONE HELP!!!

100,000= X * [(1320-2x) / pi] + {pi * [(1320-2x)/pi]} / 4

2007-09-07 15:46:32 · 5 answers · asked by joetterb 3 in Science & Mathematics Mathematics

can someone work it completely out using the quadratic formula

2007-09-07 16:16:18 · update #1

yes the x's are the same my mistake sorry
and it is in ratio to circumference... for the pi

2007-09-07 16:17:43 · update #2

5 answers

400,000 pi = 1320(4) x - 2(4) x^2 + 1320 pi - 2x pi
400,000 pi = 5280 x - 8 x^2 + 4146.9 - 6.283 x
8 x^2 - 5273.72 x +1252490 = 0
x = imaginary . . . big constant

2007-09-07 15:58:47 · answer #1 · answered by CPUcate 6 · 0 0

100,000= X * [(1320-2x) / pi] + {pi * [(1320-2x)/pi]} / 4
100,000 = (1320x -2x^2)/pi + (1320-2x)/4
4pi(100,000) = 4(1320x -2x^2) +pi(1320-2x)
400,000pi = 5280x-8x^2 +1320pi - 2pix
400,000pi - 1320pi +8x^2 -5280x +2pix =0
8x^2 - (5280-2pi)x + 398,680pi= 0
This is a quadratic equation with no real roots since b^2-4ac <0. You can find the imaginary roots by using the quadratic formula.

2007-09-07 23:10:54 · answer #2 · answered by ironduke8159 7 · 0 0

First, the "π"s in the second term cancel:
1000,000 = [x(1320 - 2x)/π] + [(1320 - 2x)/4]

Multiply both sides by 4π. This gets rid of the fractions.
400,000π = 4x (1320 - 2x) + π(1320 - 2x)

Factor out a (1320-2x)
400,000π = (1320 - 2x) ( 4x + π )

Multiply this out, and get everything in the form of ax^2 + bx + c = 0, then use the quadratic formula

2007-09-07 23:02:57 · answer #3 · answered by Anonymous · 0 0

This may seem an obvious question - but can I assume that we are talking about pi in terms of angles here (i.e. pi=180) rather than pi as the ratio of a circle to it's circumference (pi=3.14).

Obviously this makes rather a difference.

If you can put the question in context it would help.

Also - is the large X at the front of the equation the same as the small x further through the equations...

2007-09-07 23:10:57 · answer #4 · answered by piscesgirl 3 · 0 1

No solution in real numbers.

But complex numbers:
329.6073009 + 218.9070511 i
and
329.6073009 - 218.9070511 i

according to Maple 10.

MJ

2007-09-07 23:08:46 · answer #5 · answered by Maxime J 3 · 0 0

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