Finding the Least Common Multiple (LCM)?

Question

12, 20, and 35

Answer 1

35 70 105 --------------420--------
20 40 60 ---------------420-------
12 24 36 ---------------420-------
LCM is 420

Answer 2

12 = 2 x 2 x 3
20 = 2 x 2 x 5
35 = 5 x 7

LCM = 2 x 2 x 3 x 5 x7
= 12 x 5 x 7
= 60 x 7
= 420

Answer 3

420. The best way to find the LCM is factor each number and remove numbers that are common. 12 is 2*2*3. 20 is 2*2*5. 35 is 5*7. Then we take all the factors of each number and we remove any numbers that are shared or have in common: 2,(2),2,(2),3,5,(5),7 then we multiply the remaining numbers. 2*2*3*5*7=420. (The numbers in ( ) are excess factors and are to be removed to find the LOWEST common multiple. If we leave any or all in the equation, then we will have multiples, but not the LEAST COMMON MULTIPLE.)

Answer 4

The quantities are (12 x a x b) and (6 x a^2 x b^0) LCM of 12 and 6 is 12. LCM of a and a^2 is a^2. LCM of b and b^0 is b. Thus LCM of the quantities is the product of these LCMs which is 12 x (a^2) x b

Answer 5

Do the LCM's 2 at a time:
Also, use the fact that LCM(a,b) = a*b/GCF(a,b).
So LCM[12,20] = 12*20/4 = 12*5 = 60.
LCM(60,35) = 60*35/5 = 60*7 = 420.
The LCM of 12,20 and 35 is 420.

Answer 6

12 = 2*2*3
20= 2*2*5
35= 5*7
The LCM is thus 2*2*3*5*7= 420
12*35 = 420
20*21=420
35*12= 420

Answer 7

12

Answer 8

12 = 2x2x3
20 = 2x2x5
35 = 5x7
LCM(12, 20, 35) = 2x2x3x5x7 = 420

Answer 9

12=2*2*3
20=2*2*5
35=5*7
so you need 2*2*3(from the 12)*5(from the 20)*7(from the 35)

Answer 10

12 = 2 * 2 * 3
20 = 2 * 2 * 5
35 = 5 * 7

You eliminate the factors you have twice to get :
2 * 2 * 3 * 5 * 7 = 420

420 is the answer

MJ

Answer 11

420