2007-09-07 15:17:00 · 17 answers · asked by Anonymous in Entertainment & Music ➔ Polls & Surveys
Hercules, Legolas and Faramir Team .
2007-09-15 14:36:44 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Xena and Gabrielle would kick butt but Frodo would be too busy sorting out his issues with the ring whilst Legolas has an awesome aim, Faramir is a good warrior and Hercules has strength.
Team Legolas would win.
2007-09-07 15:47:38 · answer #2 · answered by ♆Şрhĩņxy - Lost In Time. 7 · 0⤊ 0⤋
Frodo would screw everything up for Xena but my girl NEVER takes no for an answer. Her chakram could slice all of Legolas's arrows and she could out sword fight Faramir anytime. Gab's a great warrior too so the two of them would carry Frodo to win the fight.
2007-09-07 17:23:55 · answer #3 · answered by Xena_fire 4 · 1⤊ 0⤋
Well, I don't know who Gabrielle is, but the Legolas, Faramir, Hercules team would definitely win. Frodo would be useless. However, Legolas is too accurate and mystical to lose to them. He would kick ****. Faramir could help too, and Hercules could rip them apart. It wouldn't even be fair.
2007-09-07 15:37:06 · answer #4 · answered by Anonymous · 0⤊ 1⤋
Xena has already tore Hercules' a new one, so theres no debating that.
Frodo is a hobbit.
Legolas is good with archery, but I don't recall him being all that good of a warrior in general.
This sounds bad, but I don't remember who Faramir was.
2007-09-09 03:55:03 · answer #5 · answered by just us4 3 · 0⤊ 0⤋
Legolas, Faramir, and Hercules!
2007-09-07 15:20:46 · answer #6 · answered by angafeabeta 4 · 0⤊ 0⤋
Xena, Gabrielle, and Frodo
2007-09-15 14:56:09 · answer #7 · answered by Anonymous · 0⤊ 0⤋
Xena Gabrielle and frodo for sure
2007-09-12 01:19:15 · answer #8 · answered by iFu 2 · 0⤊ 0⤋
Team Legolas. Frodo would cause team Xena to lose.
2007-09-07 15:19:48 · answer #9 · answered by DeCaying_Roses 7 · 1⤊ 1⤋
Legolas, Faramir, and Hercules
frodo dont get me started hed just have visions of the ring...
2007-09-07 15:22:42 · answer #10 · answered by ***My Blǿǿdy Fätê♥ 4 · 0⤊ 0⤋