x - 3 = 18
x = 21
2007-09-10 22:19:10
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answer #1
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answered by Como 7
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Solve for x.
2(x-3) = 36
2x-6 = 36
2x = 36 + 6
2x/2 = 42/2
x = 21
2007-09-07 21:43:04
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answer #2
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answered by Bonjour ♥ 4
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2(x -- 3) = 36
=> x -- 3 = 18
=> x = 21
2007-09-07 21:42:27
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answer #3
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answered by sv 7
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Distribute first. 2x-6=36. Add 6 to both sides to undo the addition and isolate the variable. 2x-6+6=36+6=2x=42. Next divide by 2 both sides to undo the multiplication. x=21. Plug in to check. 2(21-3)=36. 2(18)=36. Works!!
2007-09-07 21:44:07
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answer #4
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answered by math whiz 3
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Asked: Solve for x.
Given: 2(x â 3) = 36
Solution:
Distribute..
2(x â 3) = 36
2x - 6 = 36
Transpose...
2x = 36 + 6
2x = 42
Divide the equation by 2...
(2x = 42) / (2)
x = 21
Answer: Thus, the answer is 21!
Good luck and God bless!
2007-09-07 21:42:28
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answer #5
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answered by Anonymous
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u multiply the (x-3) by 2 so what u end up with is 2x-6=36.
after you add the six t itself and it cancels itself out cuz theres already a neg. 6...so it there no more! then then u add the six to the 36 and get 42...so it should look like this....2x=42...u then divide everything by 2 and get x=21!!!
2007-09-07 21:45:43
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answer #6
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answered by kookygurl 2
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You have two terms on the left, 2 and (x-3). The x is still trapped in the x-3 term, so divide both sides by 2 to get the term by itself.
x - 3 = 36/2
x - 3 = 18
Now to get x by itself, add 3 to both sides
x - 3 + 3 = 18 + 3
x + 0 = 21
x = 21
2007-09-07 21:40:52
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answer #7
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answered by Anonymous
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21
2007-09-07 21:39:33
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answer #8
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answered by Anonymous
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x - 3 = 18
x = 21
2007-09-07 21:41:38
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answer #9
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answered by CPUcate 6
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2x- 6 = 36
2x = 42
x = 21
2007-09-07 21:39:10
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answer #10
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answered by Mr Nodozo 2
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