2(x − 3) = 36
2007-09-07 14:36:19 · 12 answers · asked by Hck3r g0t mii psSw0rd 2 in Science & Mathematics ➔ Mathematics
x - 3 = 18
x = 21
2007-09-10 22:19:10 · answer #1 · answered by Como 7 · 0⤊ 0⤋
Solve for x.
2(x-3) = 36
2x-6 = 36
2x = 36 + 6
2x/2 = 42/2
x = 21
2007-09-07 21:43:04 · answer #2 · answered by Bonjour ♥ 4 · 0⤊ 0⤋
2(x -- 3) = 36
=> x -- 3 = 18
=> x = 21
2007-09-07 21:42:27 · answer #3 · answered by sv 7 · 0⤊ 0⤋
Distribute first. 2x-6=36. Add 6 to both sides to undo the addition and isolate the variable. 2x-6+6=36+6=2x=42. Next divide by 2 both sides to undo the multiplication. x=21. Plug in to check. 2(21-3)=36. 2(18)=36. Works!!
2007-09-07 21:44:07 · answer #4 · answered by math whiz 3 · 0⤊ 0⤋
Asked: Solve for x.
Given: 2(x â 3) = 36
Solution:
Distribute..
2(x â 3) = 36
2x - 6 = 36
Transpose...
2x = 36 + 6
2x = 42
Divide the equation by 2...
(2x = 42) / (2)
x = 21
Answer: Thus, the answer is 21!
Good luck and God bless!
2007-09-07 21:42:28 · answer #5 · answered by Anonymous · 0⤊ 0⤋
u multiply the (x-3) by 2 so what u end up with is 2x-6=36.
after you add the six t itself and it cancels itself out cuz theres already a neg. 6...so it there no more! then then u add the six to the 36 and get 42...so it should look like this....2x=42...u then divide everything by 2 and get x=21!!!
2007-09-07 21:45:43 · answer #6 · answered by kookygurl 2 · 0⤊ 0⤋
You have two terms on the left, 2 and (x-3). The x is still trapped in the x-3 term, so divide both sides by 2 to get the term by itself.
x - 3 = 36/2
x - 3 = 18
Now to get x by itself, add 3 to both sides
x - 3 + 3 = 18 + 3
x + 0 = 21
x = 21
2007-09-07 21:40:52 · answer #7 · answered by Anonymous · 0⤊ 0⤋
21
2007-09-07 21:39:33 · answer #8 · answered by Anonymous · 0⤊ 0⤋
x - 3 = 18
x = 21
2007-09-07 21:41:38 · answer #9 · answered by CPUcate 6 · 0⤊ 0⤋
2x- 6 = 36
2x = 42
x = 21
2007-09-07 21:39:10 · answer #10 · answered by Mr Nodozo 2 · 0⤊ 0⤋