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An electric dipole consists of charges +2e and -2e separated by 0.78 nm. It is in an electric field of strength 3.4 x 10^6 N/C. Calculate the magnitude of the torque on the dipole when the dipole moment is
(a) parallel to
(b) perpendicular to
(c) antiparallel to the electric field.
What is the difference between potential energies for dipole orientations parallel and antiparallel to the electric field?

2007-09-07 14:27:30 · 2 answers · asked by Hua Zhi X 1 in Science & Mathematics Physics

2 answers

Torque = [pxE] therefore

(a) zero
(b) pEsin90 = 2e*0.78*10^-9*3.4*10^6
(c) zero

2007-09-07 15:06:31 · answer #1 · answered by Snowflake 7 · 3 0

an electric dipole saved in a uniform electric field reports a stress : fake an electric dipole saved in a uniform electric field reports a torque : genuine Dipole in an exterior field evaluate an eternal dipole of dipole 2d 'p' in a uniform exterior field E, which suggests that p does not rely E nor this is brought on with the aid of E. The stress on q is qE and on -q is -qE and internet stress on dipole is 0. in spite of the incontrovertible fact that, the charges are separated so the stress act on distinctive factors, giving upward thrust to a torque (twisting stress) on the dipole. while internet stress is 0, torque is autonomous of the beginning place. Its value equals the cost of each and every stress more desirable by ability of perpendicular distance between the two antiparallel forces. it somewhat is, value of torque (t) = qE x 2a sinq In vector notationare assumed to be interior the airplane of the paper. From the above, this is chanced on that an electric dipole located in uniform electric field reports a torque which align the dipole parallel to the direction of the electrical powered field.

2016-12-16 14:20:49 · answer #2 · answered by bickley 4 · 0 0

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