Have a story problem. help!!!!?

Question

The sum of the measures of the angles of a parallelogram is 360. In the parallelogram below, A and D have the same measure as well as angles C and B. If the measure of angle C is twice the measure of angle A, find the measure of each.

Answer 1

First, list everything in proportion to each other:
2A+2D=C=B

Or you could just say:
2A=C

Now, we know that all of these angles add up to 360. So:
2A+2A+A+A=360

Then you solve using algebra:
6A=360
A=360/6
A=60

So now we calculate all the other angles. Remember:
2A=2D=C=B

So:
A=60
D=60
B=60*2=120
C=60*2=120

Answer 2

If the measures of angles A and D are equal, and the measures of angles B and C are equal but different than A and D, then angles A and D are opposite angles and angles B and C are opposite angles.

Let
x = m 2x = m
We also have

m m
Therefore

m x = 60°
2x = 120°

m m m m

Answer 3

I forgot how to show the problem but i remember the answers:
A=60
B=120
C=120
D=60

Add them up and they equal 360 degrees and C is twice as A.