Potassium (K) occurs in seawater at a rate of 0.392 g of K for every kilogram of seawater. Calculate the?

Question

volume of seawater (in liters) needed to extract 2.2 X 104 tons of K. (Density of seawater is 1.03 g/mL.)

Answer 1

Use ratios

Pottasium is present at 0.392 g / 1000 g of seawater. That is 0.0392%

So how may tons of seawater do you need to get the tons of K you want. Use the percent above to calculate. Once you have the tons multiply by 1,000 to get Kg. Now divide by the density to convert to liters.

Answer 2

First, we will assume you mean the TONNE, or 1000 kg. So we can set up a proportion to find the kg of waters required and then convert to volume.
The proportion:
.392x10^-6 Tonne/Kg = 2.2x10+4 Tonne/ X Kg
X= 2.2/.392 x10^10 kg of seawater.
Divide that by 1.03 to get you volume in Liters.