15= 3 (7y - 2)
=> 15 = 21y - 6
=> 21 = 21y
=> 1 = y
ANS y=1
5/8x - 1/2 = 3/4
=> 5x - 4 = 6......X by LCM=8
=> 5x = 10
=> x = 2
ANS x=2
QED
2007-09-07 10:24:36
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answer #1
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answered by harry m 6
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15= 3 (7y - 2)
15 =21y-6
21= 21y
1= y
5/8x - 1/2 = 3/4
Multiply by 8 getting
5x -4 =6
5x = 10
x=2
2007-09-07 17:26:23
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answer #2
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answered by ironduke8159 7
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15 = 3 (7y - 2)
15 = 21y - 6
21 = 21y
y = 1
5/(8x) - 1/2 = 3/4
5/(8x) = 3/4 + 1/2
5/(8x) = 3/4 + 2/4
5/(8x) = 5/4
8x = 4
x = 4/8
x = 1/2
2007-09-07 19:06:51
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answer #3
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answered by Kemmy 6
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Multiply 3. 21Y - 6. Add 6 to both sides 21 = 21Y divide by 21. Y = 1. Or divide both sides by 3. 5 = 7y-2. Add 2 to both sides 7= 7 y. divide by 7 1 = y.
2007-09-07 17:31:18
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answer #4
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answered by Big D 1
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3(7x-2) = 15
Invert Operations
(7x-2) = 15/3
(7x-2) = 5
7x = 5+2
7x = 7
x = 7/7 = 1
5/8x - 1/2 = 3/4
Invert Operations
5/8x = 3/4 + 1/2
5/8x = 5/4
x = 5/4 ⢠5/8 = 2
⢠= Divide
2007-09-07 17:32:13
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answer #5
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answered by Anonymous
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For the first one, multiply 3 by the contents of the parentheses. Then solve normally.
For the second one, add 1/2 to both sides, then cross-multiply.
2007-09-07 17:24:56
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answer #6
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answered by Brian L 7
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the first is y=1
and the second is x=2
2007-09-07 17:26:32
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answer #7
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answered by L337est 4
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