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How do you divide monomials by monomials
with exponents?


e.g>>

2a^4b^3÷a^2b


-4w^3x^5 ÷ (-2w^2x^2)


-9f^3g^5h^2 ÷ 6fg^2h

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oh and multiplying monomials by monomials?

is the answer to this rite ?
(2yz)(-3y^3)
= -6y^4z
if its not rite can you explain what i did wrong?

2007-09-07 09:56:17 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

2a^4b^3 ÷ a^2b =
2(a^4/a^2)(b^3/b) =
2 (a/a)(a/a)(a/1)(a/1) (b/b)(b/1)(b/1) =
2 (a)(a) (b)(b) =
2a^2b^2
Note that 4 - 2 = 2 and 3 - 1 = 2,
so division of like terms can be done by subtracting exponents.

-4w^3x^5 ÷ (-2w^2x^2) =
(-4/-2) (w^(3-2)) (x^(5 - 2) =
2wx^3

. . . and so forth.

Your multiplication is correct.

2007-09-07 10:47:27 · answer #1 · answered by Helmut 7 · 1 0

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