Physics What is the acceleration vector of...?

Question

Yes, this is homework help. The question is as poses,

"What is the direction of the acceleration vector of a person on the spinning Earth if a person is (a) at the equator? (b) at some other latitude? (c) at the poles?"

Answer 1

someone on the earth will accelerate. The speed may be constant but the change in direction results in acceleration [pointing towards the center-axis for a and b]

In case c the person himself is spinning. Not sure here. I now think it points inwards towards the center axis of the person. (You also have something here called the angular acceleration. This is in the direction of the axis around which the person spins.)

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not asked sorry:
a = v^2/r, where r is the distance from the person to the earths axis.

a] a = (0.5 km/s )^2 / (6 x 10 ^3 km )

Answer 2

Angular acceleration is r(omega)^2, the place r is the radius and omega angular speed in rad/sec. this might translate to V^2/r for linear acceleration of around action at consistent speed. linear acceleration = 3 hundred*3 hundred/25000=ninety/25 meters /sec^2 =3,6 meters/sec^2. The acceleration is barely due substitute in direction of the fee vector and factors contained in direction of the tangent to the curve at that component, i.e. perpendicular to the radial line, yet interior the comparable plane. there is no improve in linear speed hence no horizontal acceleration. you need to use the above 2 equations to unravel maximum issues related to around action.

Answer 3

What he said.
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