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if you know that sin x = ±1/√2 how do you find out what x is?

2007-09-07 09:19:24 · 4 answers · asked by fhsdjfsd 2 in Science & Mathematics Mathematics

4 answers

You memorize cosine and sine for key values like 30, 45, 60, and 90 degrees, know what those angles are in terms of radians, and keep a mental picture of the coordinate axes in your head.

Then you would know that sin(45) = sqrt(2)/2. You would also know that sin(90+45) = sqrt(2)/2. And so forth.

[I'm assuming you know that 1/sqrt(2) = sqrt(2)/2.]

2007-09-07 09:27:45 · answer #1 · answered by PMP 5 · 0 0

Use a calculator.

x = sin^-1(±1/√2) = ± 45

2007-09-07 16:25:24 · answer #2 · answered by gebobs 6 · 0 0

If you draw a right angled triangle with two 45 degree angles and two sides of one unit length. Then the hypotenuse will be sqrt(1^2+1^2) ie sqrt2. Since sin(theta) is equal to opposite over hypotenuse, then sin(theta) = 1/sqrt2. So theta equals 45 degrees or Pi/4rads.

2007-09-07 16:52:45 · answer #3 · answered by eazylee369 4 · 0 0

sorry no can do

2007-09-07 16:26:26 · answer #4 · answered by Anonymous · 0 1

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