Express the quadratic function f(x) = - x ^2 + 4x - 12 in standard
form.
a. -(x - 2) ^2 - 8
b. -(x + 2)^2 - 14
c. (x + 2) ^2 + 12
d. -(x - 4) ^2 - 2
e. (x - 4) ^2 - 24
2007-09-07 07:11:10 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The way to figure the answer out is to expand each of the functions listed. For a.),
-(x - 2)^2 - 8
= -(x^2 - 4x + 4) - 8
= -x^2 + 4x - 4 - 8
= -x^2 + 4x - 12.
The key here is being able to expand each of the functions. If you know how to do that, you'll be in good shape for any other questions like this. :)
2007-09-07 07:27:54 · answer #1 · answered by RustyL71 4 · 0⤊ 0⤋
- x^2 + 4x - 12
-(x^2 - 4x) - 12
-(x^2 - 4x + 4) - 12 - (-4)
-(x - 2)^2 - 8
A
2007-09-07 14:27:21 · answer #2 · answered by Mathematica 7 · 0⤊ 0⤋
f(x)=-x^2+4x-12
=-{(x^2-4x+2^2)+12-2^2}
=-{(x-2)^2+12-4}
=-{(x-2)^2+8}
=-(x-2)^2-8 ie.,a ans
2007-09-07 14:26:15 · answer #3 · answered by MAHAANIM07 4 · 0⤊ 0⤋
The answer is a., i.e., -(x-2)^2-8
2007-09-07 14:22:28 · answer #4 · answered by Eechhutti 2 · 0⤊ 0⤋
a.
2007-09-07 14:29:33 · answer #5 · answered by ironduke8159 7 · 0⤊ 0⤋