Show work please! I'M CONFUSED ....
2007-09-07 07:04:05 · 7 answers · asked by nealee 2 in Science & Mathematics ➔ Mathematics
Come on peoples!!!!!!!! Im dying here!!!!!! LOL! :-)
2007-09-07 07:14:12 · update #1
16x^4-81 -->
(4x^2-9)(4x^2+9) -->
(2x-3)(2x+3)(4x^2+9)
2007-09-07 07:12:40 · answer #1 · answered by Anonymous · 1⤊ 0⤋
The above answer is incomplete. The 4x^2-9 term can be further factored to 2x+3 and 2x-3
2007-09-07 14:13:13 · answer #2 · answered by cattbarf 7 · 1⤊ 0⤋
this is the difference in two perfect squares. A^2 -B^2 can be factored into (A+B)(A-B).
Your expression can be factored into (4X^2+9)(4X^2 - 9)
The second can be factored further into (2x + 3)(2x - 3)
so the answer is (4x^2 + 9)(2x+3)(2x-3)
2007-09-07 14:29:41 · answer #3 · answered by davidosterberg1 6 · 0⤊ 0⤋
Even more :
(2x - 3) (2x + 3) (4x^2 + 9)
There was a second difference of squares.
MJ
2007-09-07 14:13:43 · answer #4 · answered by Maxime J 3 · 1⤊ 0⤋
16x^4 - 81
=(4*x^2+9)*(4*x^2-9)
= (4*x^2+9)*(2x+3)*(2x-3)
2007-09-07 14:16:04 · answer #5 · answered by Eechhutti 2 · 1⤊ 0⤋
Difference of two squares
(4x^2 + 9) (4x^2 -9 )
2007-09-07 14:10:38 · answer #6 · answered by dwinbaycity 5 · 1⤊ 1⤋
=16x^4-81
={(4x^2)^2-(9)^2}
=(4x^2-9)(4x^2+9)---using a^2-b^2=(a-b)(a+b)
={(2x)^2-(3)^2}(4x^2+9)
=(2x-3)(2x+3)(4x^2+9) ---using a^2-b^2=(a-b)(a+b)------------------ans
2007-09-07 14:37:54 · answer #7 · answered by MAHAANIM07 4 · 0⤊ 0⤋