to many numbers eat the pi
2007-09-07 06:58:01
·
answer #1
·
answered by Anonymous
·
0⤊
2⤋
006 answered right for A, B and C and b
Though, a) has only 2 significant figures because the zeros are just like if you were writing 00003.1416 for pi; they do not mean nothing else than giving the idea of how big is the number (positionning it right).
b) 5 significant figures; when there are zeros at the end of a number, they represent that the precision of the measure was up to these number positions, so they count!
MJ
2007-09-07 07:04:51
·
answer #2
·
answered by Anonymous
·
0⤊
0⤋
besides the reality that this might sound stupid, important discern are incredibly frankly, discern that are important. enable me clarify, if a variety is 3000, the three 0s are important, because of the fact without them, it could be 3 hundred, or 3. besides the fact that, in 002, the 0s at the instant are not important because of the fact removing them might pass away the variety 2. yet another occasion is 0.002, the 0s are important, besides the fact that 2.0000 the 0s at the instant are not important, (till in a mathematical term the place it will develop the accuracy, yet to no longer subject approximately this.) So, a hundred thirty.0, the a hundred thirty are the 1st 3 important discern, so a hundred thirty.0 to 3 SigFig is a hundred thirty. 0.03 is purely 0.03, and 462.0 is purely 462. 0.0.5 could be 0.0.5, leaving the 0s. So, if somebody tells you to alter a variety to countless important figures, you should seem for the set volume of numbers that are important. something which would be complicated is that if there is something alongside with 34203, and individuals say make it 3 SigFig - you seem on the 1st 3 numbers that are important, 342, and then seem on the different 2. they're nonetheless important, so which you adjust them to 0s. In scientific words, 0.039 to 2 SigFig might become 3.9 x 10(to the ability of -2). wish this helped, a number of this per danger faulty, its been 4 years considering I did this!!
2016-10-10 03:37:11
·
answer #3
·
answered by Anonymous
·
0⤊
0⤋
Question B:
(a) 2 (the 0's in front of the digits are not significant--they just hold the place.)
(b) 5 (the last zero is significant. otherwise, it wouldn't be there)
2007-09-07 07:02:18
·
answer #4
·
answered by hcbiochem 7
·
0⤊
0⤋
A) 3.1
B) 3.14159265
C) 3.14159265898
a) 5? (not sure if leading zeroes after the decimal place are significant, but I believe they are... it's been a while)
b) 5, trailing zeroes after the decimal place are significant.
2007-09-07 06:59:59
·
answer #5
·
answered by 006 6
·
0⤊
0⤋
Question A
A) 3.1
B) 3.14159265
C) 3.14159265898
Question B
A) 2
B) 4
2007-09-07 07:04:52
·
answer #6
·
answered by Michael B 1
·
0⤊
0⤋
I have no clue. Is this like your homework or something?
2007-09-07 06:58:33
·
answer #7
·
answered by Katy M 2
·
0⤊
1⤋
3.141592654
2017-01-14 03:26:00
·
answer #8
·
answered by Anonymous
·
0⤊
0⤋