Find the domain and range of the function:
G(x) = (x^ 2 - 16)(square root)
a. Domain (-∞,-4] ∪ [4,∞), Range [4,∞)
b. Domain (-∞,-4] ∪ [4,∞), Range [-4,∞)
c. Domain (-∞,-4] ∪ [4,∞), Range [0,∞)
d. Domain (-∞,-2] ∪ [2,∞), Range [2,∞)
e. Domain (-∞,∞), Range [0,∞)
2007-09-07 06:53:49 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Look at the graph
http://i233.photobucket.com/albums/ee319/fjfk/sqrt.jpg
and see the answer is c.
2007-09-07 07:07:33 · answer #1 · answered by ? 5 · 0⤊ 0⤋
The answer has to be C because you do not want a square root of a negative value so you do not want anything that will be squared to a smaller value than 16 so exclude the numbers between -4 and 4 for the domain. Range can not be negative and will start at zero. G(x) = 0 when X= -4 or 4.
2007-09-07 14:03:25 · answer #2 · answered by Mike B 2 · 0⤊ 0⤋
c.
If x is between -4 and 4 (not inclusive) you would get a negative number under the radical. Can't take the square root of a negative number. But if you square any negative number less than -4, you'll get a positive number that is greater than 16...
All square roots have to be greater than of equal to 0, making the range [0,infinity).
2007-09-07 13:57:36 · answer #3 · answered by SoulDawg 4 UGA 6 · 0⤊ 0⤋
dude the domain is (-â,-4] u [4,â)
and to find ther range we must know that sqr root of any number is always greater than zero.so the range of given function os [0,â).
option C.
2007-09-07 14:02:30 · answer #4 · answered by nawaz_xan6 2 · 0⤊ 0⤋