(1/2) x^2 - (11/2) (x) + 15 = 0
multiply by 2
x^2 - 11x + 30 = 0
(x)^2 - 2(1) (11/2) x + (11/2)^2 - (11/2)^2 + 30 = 0
(x)^2 - 2(1) (11/2) x + (11/2)^2 - (121/4) + 30 = 0
(x- 11/2)^2 = 121/4 - 30
(x - 11/2)^2 = 1/4 = (1/2)^2
x - 11/2 = +1/2 or - 1/2
x = 11/2 + 1/2 or 11/2 - 1/2
6 or 5
2007-09-07 07:28:50
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answer #1
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answered by mohanrao d 7
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(1/2)x ^2 - (11/2)x + 15 = 0
First, multiply both sides by 2 to get rid of fraction.
x^2 - 11x + 30 = 0
x^2 - 11x = -30
take the 11, divide it by two, then square it. Add that to both sides.
x^2 - 11x + (11/2)^2 = -30 + (11/2)^2
(x - 11/2)^2 = -30 + 121 / 4
(x - 11/2)^2 = -120/4 + 121/4
(x - 11/2)^2 = 1/4
take square root of both sides
x - 11/2 = +- 1/2
x = 11/2 +- 1/2
x = (11/2 - 1/2) AND (11/2 + 1/2)
x = (10/2) AND (12/2)
x = 5 AND 6
2007-09-07 06:47:41
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answer #2
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answered by Mathematica 7
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The quadratic equation "general solution" is based on completing the square, so it doesn't make sense to reinvent the wheel. So.....
x = 11/2 +/- sqrt([121/4]-4*1/2*15)
x = 11/2 +/- 1/2 , x= 5 or 6 (b)
2007-09-07 06:46:23
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answer #3
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answered by cattbarf 7
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1/2x ^2 - 11/2x + 15 = 0
x ^2 - 11x + 30 = 0
x ^2 - 2*x*(11/2) + (11/2)^2 + 30 - (11/2)^2= 0
(x - 11/2)^2 = (11/2)^2 - 30
(x - 11/2)^2 = 121/4 - 30
(x - 11/2)^2 = 1/4
(x - 11/2) = ± 1/2
x = 11/2 ± 1/2
x = 6, 5
2007-09-07 06:45:24
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answer #4
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answered by psbhowmick 6
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1/2 x^2 - 11/2 x + 15 = 0
x^2 - 11x + 30 = 0 (* eq by 2)
x^2 - 11x = -30
x^2 - 11x + (11/2)^2 = (11/2)^2 - 30
(x - 11/2) ^ 2 = 121/4 - 120/4 = 1/4
(x - 11/2) = +1/2 or -1/2
x = 11/2 + 1/2 = 6 or 11/2-1/2 = 5
Ans is b
2007-09-07 06:43:23
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answer #5
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answered by norman 7
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1/2x^2-11/2x+15=0
multiply both sides by 2;
x^2-11x+30=0
[(x-11/2)^2+30-121/4]=0
(x-11/2)^2+(120-121)/4=0
(x-11/2)^2=1/4
take sq. roots of two sides;
x-11/2= +/- 1/2
x=11/2+/- 1/2
=6,5ANS.
2007-09-07 06:51:17
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answer #6
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answered by Anonymous
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b. x=5 or 5
2007-09-07 06:55:21
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answer #7
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answered by ? 5
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