here is what it says..
<1 and <2 are complimantary angles. Find the measures of the angles when m<1 = (x-10) degrees and m<2 = (2x + 10)degrees.
Are the two angles equal? I am so confused. What's the answer?
2007-09-06 19:30:59 · 5 answers · asked by courtney j 1 in Science & Mathematics ➔ Mathematics
complimentary angles = 90 degrees
< 1 + <2 = 90 degrees
(x-10) + (2x + 10) = 90 degrees
x - 10 + 2x + 10 = 90
3x = 90
x = 30
<1 = (x - 10)
= 30 - 10 = 20 degrees
<2 = 2x + 10
= 2(30) + 10 = 70 degrees
the two angles are not equal
2007-09-06 19:42:52 · answer #1 · answered by ferdie 2 · 0⤊ 0⤋
The answer is 42 (c.f. Doug Adams, 'Life, the Universe, and Everything.')
Seriously, 'Complimentary angles' just means that they add up to 90 degrees ('supplementary' means they add up to 180 degrees)
So you have 2 angles (x-10) and (2x+10) that add up to 90 (for some x value) How about
(x-10) + (2x+10) = 90
then 3x = 90 and x = 30 so the angles are 20 and 70 degrees.
That didn't hurt too much, did it? âº
Doug
2007-09-07 02:48:15 · answer #2 · answered by doug_donaghue 7 · 0⤊ 0⤋
(x-10)+(2x + 10)=90
3x=90
x=30
<1=30-10=20
<2=2.30+10=70
2007-09-07 02:45:16 · answer #3 · answered by iyiogrenci 6 · 0⤊ 0⤋
Complimentary angles... check your definition.
Cannot be equal unless both are 45 degrees, which in this case, given your equations, are clearly not.
2007-09-07 02:39:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
the answer is i am also confused. heeeeeeeeelp.
i think the answer is yes. but i am only 50% sure.
2007-09-07 02:37:03 · answer #5 · answered by raspberry 2 · 0⤊ 0⤋