Solve the system?
|x+2y-2z=-1|
|x+3y+z=10|
|2x+6y+2z=20|
2007-09-06 18:41:43 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
|x+2y-2z=-1|
|x+3y+z=10|
|2x+6y+2z=20|
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4x+11y+z=29
i just added them all up. i don't know really know what i was suppose to do so yeah. A for effort? go me!
2007-09-06 18:47:46 · answer #1 · answered by raspberry 2 · 0⤊ 0⤋
Equation 2 and Equation 3 are identical thus you have given but two equatiions to find 3 variables.
Over and out!
2007-09-07 04:37:28 · answer #2 · answered by Como 7 · 2⤊ 0⤋
the solution is that its unsolvable. The second and third line only differ by a x2 difference which doesnt change the values for the variables. that actually leaves two equations with three variables which you cannnot solve.
I think its unsolvable or all the lines are parallel.
2007-09-07 01:47:24 · answer #3 · answered by Anonymous · 0⤊ 1⤋
omg i love these problems. haha just use crammers rule. which is the best and easiest method ^_^
since the determinate in this system is 0 then the solution to this problem. the system is dependent.
2007-09-07 02:32:49 · answer #4 · answered by ★→Damian←★ 4 · 0⤊ 0⤋