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2007-09-06 18:05:12 · 6 answers · asked by The Prophyt 2 in Science & Mathematics ➔ Mathematics
you cannot factor this equation you need to use the quadratic formula
the answer that you should get is
-4+4(radical3)/3
-4-4(radical3)/3
2007-09-06 18:19:57 · answer #1 · answered by SK07KS 2 · 1⤊ 2⤋
You have to split the coefficient of x i.e. 24, into two term whose algebraic sum is 24 and product is equal to the product of the coefficient of x^2 and constant term i.e. 3 and 32.
The product of 3 and 32 = 96
Split 24 into two terms whose sum is 24 and product is 96.
There are no such factors of 24. The factorisation of the expression is not possible.
2007-09-06 18:21:21 · answer #2 · answered by Indian Primrose 6 · 0⤊ 0⤋
The zeros are -4 + 4root(3)/3 and -4 - 4* root (3)/3
I would leave it as is. There is no simpler form with just integral coefficients.
2007-09-06 18:14:43 · answer #3 · answered by jimmyp 3 · 0⤊ 0⤋
=3(x^2 + 8x + 16) + 32 - 48
=3(x+4)^2 - 16
={sqrt(3)(x+4) + 4}{sqrt(3)(x+4) -4}
2007-09-06 18:26:25 · answer #4 · answered by Snoopy 3 · 0⤊ 0⤋
could you show me the answer? cause there's no answer to your question. and i am certainly sure!!!
2007-09-06 18:19:17 · answer #5 · answered by reigningbreeze 2 · 0⤊ 0⤋
Does not factorise.
2007-09-06 21:44:18 · answer #6 · answered by Como 7 · 0⤊ 0⤋