Question Details: A truck starting from rest (not moving) along a straight road has an acceleration of 1.7 m/s squared.
How far has it gone after
1.2 s?
2.4 s?
3.6 s?
2007-09-06 14:47:05 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Here,initial velocity u=0,a=accelaration/s^2
=1.7
We know that
s=1/2 at^2,when u=0,where s=distance travelled
1)s=1/2*(2)^2
=1/2*4
=2 m
2)s=1/2*(4)^2
=1/2*16
=8 m
3)s=1/2(6)^2
=1/2*36
=18 m
2007-09-06 14:59:50 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Since it is starting from rest, the formula to use is d = 1/2 at².
2007-09-06 21:54:59 · answer #2 · answered by Marvin 4 · 0⤊ 0⤋
final speed = 2 x 1.7 = 3.4
average speed = 1.7
distance = 1.7 x 2 = 3.4
again final = 6.8
ave = 3.4
distance = 3.4 x 4 = 13.6
f = 10.2
ave = 5.1
d = 30.6
2007-09-06 22:19:33 · answer #3 · answered by Beardo 7 · 0⤊ 0⤋