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The problem is cos(pi/3 - pi/6)
I'm thinking it's 1/2 - sqrt3/2 which equals -.3660
Is this correct or am I doing the problem wrong?

2007-09-06 14:40:54 · 3 answers · asked by Nicky 2 in Science & Mathematics Mathematics

lobosito, i'm asking because this problem is not explained whatsoever in my book

2007-09-06 14:56:08 · update #1

3 answers

I like degrees better than radian

pi/3 = 60 pi/6 = 30
cos(60-30) = cos(30) = sqrt(3)/2


Cos(a-b) is not eq cos(a) - cos(b)

2007-09-06 14:51:37 · answer #1 · answered by norman 7 · 1 0

cos(a-b) = cos a cos b +sin a sin b
Why don't you read in the manual?

2007-09-06 21:53:33 · answer #2 · answered by Theta40 7 · 0 0

www.webmath.com should be able to assist you!

2007-09-06 21:50:53 · answer #3 · answered by skittles8553 4 · 0 0

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