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x^2-y=0 ????
HELP!!!!!

2007-09-06 14:09:34 · 1 answers · asked by Catherine D 1 in Science & Mathematics Mathematics

1 answers

Let (x, y) be an arbitrary point on the curve (satisfy the equation (x)^2 - (y) = 0).
If the curve is symmetric with x-axis, (x, -y) must also on the curve (satisfy the equation).
If the curve is symmetric with y-axis, (-x, y) must also on the curve (satisfy the equation).
If the curve is symmetric about the origin, (-x, -y) must also on the curve.
Now, (x)^2 - (-y) = x^2 +y = 0 is a different equation, the curve can not be symmetric with x-axis.
(-x)^2 - (y) = x^2 -y = 0 is the same equation, the curve must be symmetric with y-axis.
(-x)^2 - (-y) = x^2 +y = 0 is a different equation, the curve can not be symmetric about the origin.

2007-09-07 04:59:54 · answer #1 · answered by Hahaha 7 · 0 0

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