make a counterexample for this conjecture plz??
2007-09-06 13:53:22 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
a rectangle 1x9 has a perimeter of 20 and an area of 9, while a recangle of 5x5 has a perimeter of 20 and an area of 25. so that is a counter example to the conjecture.
2007-09-06 13:59:06 · answer #1 · answered by Piglet O 6 · 0⤊ 0⤋
a rectangle 8 by 2 has a perimeter of 20 and an area of 16.
a rectangle 6 by 4 has a perimeter of 20 and an area of 24.
2007-09-06 20:57:27 · answer #2 · answered by KRE 3 · 0⤊ 0⤋
A rectangle that was 8x2 would have a perimeter of 20 ft. and an area of 16 sq ft. A rectangle that was 6x4 would have a perimeter of 20 ft. but an area of 24 sq. ft. Therefore two different rectangles with the same perimeter will not always have the same area.
2007-09-06 20:57:59 · answer #3 · answered by Aquamarina 3 · 0⤊ 0⤋
rectangle 1 : length= 6 ft. width= 4 ft. perimeter= 20 feet
area = 6X4 = 24
rectangle 2: length= 5ft. width= 5 ft. perimeter = 20 feet area= 5X5 = 25
2007-09-06 20:59:12 · answer #4 · answered by Whiz 3 · 0⤊ 0⤋
That only works for a circle.
2007-09-06 20:58:13 · answer #5 · answered by Robert S 7 · 0⤊ 0⤋
i have no idea lmao i think so
2007-09-06 20:57:15 · answer #6 · answered by ladeladeladeladelade 2 · 0⤊ 0⤋
5,5,5,5=20,25
9,9,1,1=20,9
2007-09-06 20:58:40 · answer #7 · answered by jdale18 2 · 0⤊ 0⤋