a falling stone fall take .3 s to travel past a window 2.2 m tall from what height above the top of the window

Question

i'm learning about acceleration due to gravity and velocity

Answer 1

The velocity of the stone from rest is
v(t)=-g*t^2
and displacement is
d(t)=-.5*g*t^2

Here's a way to solve this

The velocity of the stone at the top of the windo is v1
and
2.2=v1*0.3+.5*9.8*0.3^2
solve for v1
then, using v(t)
v1=g*t solve for t, which is the time from starting to fall to the top of the window
with t
d(t)=.5*g*t^2, solve for d, which is the distance above the window the stone was dropped.

j

Answer 2

you are able to resolve this difficulty by ability of applying the formulation s = a million/2 at^2 the place s is the entire distance travelled a = 9.80 and t = 0.28 seconds. resolve for s and don't overlook to subtract the top of the window to get the respond