Balance these chemistry equations???? PLZZZZ!!!!?

Question

Write the balanced equations for these solutions

A.) NaClO + (Na2S2O3 in NaOH) ---->

B.) NaClO + (KI in NaOH) ----->

C.) NaClO + (Na2SO3 in NaOH)

PLease list all the equations, balanced, because i have no idea what the products look like, since the second set of reactions are in sodium hydroxide.

Answer 1

First, you need to consider if there are any reduction- oxidation (redox) reactions, by checking the corresponding "Standard Reduction Potentials", say, from the reference I listed below. Here are a few concerned:
ClO− + H2O + 2e− → Cl− + 2OH− 0.89
S4O6 2−(aq) + 2e− → 2 S2O3 2−(aq) 0.169
I2(aq) + 2e− → 2I− 0.615
SO4 2− + H2O + 2e− → SO3 2− + 2OH− -0.93
These indicate that ClO− is a reasonably strong oxidizing agent. The reaction rate for (B) is the slowest. Anyway, using the first equation to subtract each one of the others, we get:
ClO− + H2O + 2 S2O3 2−(aq) → Cl− + 2OH− + S4O6 2−(aq)
ClO− + H2O + 2I− → Cl− + 2OH− + I2(aq)
ClO− + SO3 2− → Cl− + SO4 2−
Put in the Na+ ions, we finally get:
NaClO + H2O + 2 Na2S2O3 → NaCl + 2NaOH + Na2S4O6
NaClO + H2O + 2 NaI → NaCl + 2NaOH + I2(aq)
NaClO + Na2SO3 → NaCl + Na2SO4

Answer 2

First we need the balance equation which is 4K2+O2--> 2K20 ~If 45.2L of O2 at STP reacts with excess K, how many moles of K2O are produced? *45.2L O2| 1mol O2| 2mol K2O| 94.196 grams K20 --------------------------------------..... = 380.15grams K20 | 22.4 L | 1mol O2 | I mol K2O ~What volume of O2 at STP is needed to react with 45.2g of K? *45.2grams K| 1mol K | 1mol O2| 22.4L --------------------------------------..... 6.47L O2 | 39.098g K| 4mol K | 1mol O2 ~An excess of oxygen gas reacts with 2.4x10^24 atoms of K. How many formula units of K2O are made? *2.4x10^24 atoms K| 1mol K | 2mol K2O| 6.02x10^23 --------------------------------------..... = 2.4x10^24 |6.02x10^23| 2mol K | 1mol K2O (I would double check the power of the 10) ok so I showed my work the way my teacher showed me to set up stoichiometry problems. you multiply all the way across then divede the bottome across. (for example the first problem would be 45.2x1x2x94.196/22.4/1/1=380.15) i'm not sure how to explain each problem but I hipe if you see which numbers to use you can see where I got them from. Hope this helps.