An oceanic depth-sounding vessel surveys the ocean bottom with ultrasonic waves that travel 1536m/s in seawater. how deep is the water directly below the vessel if the time delay of the echo to the ocean floor and back is 7s?
2007-09-06 11:17:52 · 4 answers · asked by Ebony S 1 in Science & Mathematics ➔ Physics
It should be the amount it travels in 7/2 seconds or 3.5 x 1536 = 5,376 meters.
2007-09-06 11:22:12 · answer #1 · answered by jimmyp 3 · 0⤊ 0⤋
If you do the arithmetic of making a round trip in 7 seconds then 1 way was 3.5 seconds for sound traveling at 1536 m/sec
That give 5376 m or 5.376 km
2007-09-06 11:24:42 · answer #2 · answered by Rich Z 7 · 0⤊ 0⤋
7 s represents twice the depth...
3.5 s is the time required to travel the distance once.
1536 m/s * 3.5 s = 5376 m
MJ
2007-09-06 11:23:41 · answer #3 · answered by Anonymous · 0⤊ 0⤋
distance=velocity x time. v=1530m/s t=5/2=2.5s. d=1530x2.5=3825m. I divide the time by 2 reason that replaced into the time the wave took to hit the sea floor and back and that's double the gap we are finding for as a result i had to divide by 2 to get the intensity that's 3825m.
2016-12-31 14:45:44 · answer #4 · answered by Anonymous · 0⤊ 0⤋