The selling price of a refrigerator is $584. If the markup is 25% of the dealer's cost, what is the dealer's cost of the refrigerator? (please show work)
2007-09-06 10:17:56 · 6 answers · asked by aajain03 1 in Science & Mathematics ➔ Mathematics
$438
Subtract 25% of $584
2007-09-06 10:23:58 · answer #1 · answered by Schmoopy 2 · 0⤊ 2⤋
Take 584 divide by 1.25 yields $467.20.
As confirmation, 467.2 x 1.25 = 584.
I'm in business, doing markups every day.
2007-09-06 10:28:08 · answer #2 · answered by hottotrot1_usa 7 · 1⤊ 0⤋
Let C = dealer's cost
You pay dealer's cost plus the markup
C + .25C = 584
1.25C = 584
C = 584/1.25 = 467.20
2007-09-06 10:26:31 · answer #3 · answered by Anonymous · 1⤊ 0⤋
okay.
set up a proportion.
x over 584 equals 25 over 100.
cross multiply.
then you should get a number amount for x.
take that amount and ADD it to the original selling price
2007-09-06 10:24:53 · answer #4 · answered by cara 2 · 0⤊ 2⤋
$548 x .25 = $146 (25% of $548)
$548 - $146 = $438 (Dealer's cost)
Check: $438 + $146 =$584.00
2007-09-06 10:26:47 · answer #5 · answered by Anonymous · 0⤊ 1⤋
$584.00 x 1.25= $730.00
2007-09-06 10:24:37 · answer #6 · answered by Anonymous · 0⤊ 3⤋