I need help with this one quick. Anyone please help me out and please just dont answer it. If you can do the steps, open up paint or a drawing program and draw the steps, include the trig circle, its not hard to draw. Just save it as a picture and send it to me through e-mail. It would be greatly appreciated.
Thanks
2007-09-06 09:54:00 · 5 answers · asked by neverisenough 1 in Science & Mathematics ➔ Mathematics
Hint: draw a triangle in the third quadrant with an opposite side of -2 and an adjacent side of -5 (they have to be negative to be in the third quadrant). Now, find the hypothenuse and figure out what cos(theta) is. The previous poster is WRONG: the cosine is negative in that quadrant.
2007-09-06 10:01:21 · answer #1 · answered by mathematician 7 · 0⤊ 0⤋
4/5pheta 2.5 cosine so take 2.5 times 4/5 and that will be your cosine pheta. Double check on google.com seach engine but that should be something weird like that
2007-09-06 10:03:13 · answer #2 · answered by stallion 4 · 0⤊ 0⤋
tan pheta = 2/5 => sin pheta = - 2/sqrt(29) , minus because phetapi/2
|b
| (2)
|____(5)____a
length ab is sqrt(25 + 4) = sqrt(29)
cos a = 5/sqrt(29)
tan a = 2/5
2007-09-06 09:59:36 · answer #3 · answered by gjmb1960 7 · 0⤊ 1⤋
ok. at first you may desire to draw a unit circle and label sin and cos as + or - in each Quadrant 1Q- the two are +, 2Q-sin is +, cos is -, 3Q-sin is -, cos is +, 4Q- sin is -, cos is +. Now, the different element is it is not pheta that's "theta" Greek letter. Tan (theta) = sin(theta)/cos(theta) = (y/r)/(x/r) = y/x yet for it to be undefined x has to =0 Tan(theta) is undefined whilst cos(theta) = 0 and that occurs at -3pi/2, -pi/2, pi/2, 3pi/2..etc.
2016-11-14 09:12:12 · answer #4 · answered by jannelle 4 · 0⤊ 0⤋
Its theta (θ) not pheta lol
2007-09-06 10:13:17 · answer #5 · answered by plolol 2 · 0⤊ 0⤋