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How do I find the sequences?
-1, 0, 3, 8, 15, 24,
0, 3, 8, 15, 24, 35

2007-09-06 09:40:45 · 12 answers · asked by Jilly C 2 in Science & Mathematics Mathematics

12 answers

well just look at it!

it's the previous term plus the next odd in the squence.

so add 1 then 3 then 5 then 7 then 9

2007-09-06 09:43:05 · answer #1 · answered by Mr. Midget 3 · 0 1

Look at the difference between the first number (-1) and the next (0).
The difference is 1.

Now look at the difference between the next two (0 and 3).
The difference is 3.

If you continue this, you will find that the difference between a number and the next in the sequence is two more than the difference between that number and the previous number in the sequence.

So, the next number in the first sequence is 35, because it is 11 more than 24 which is 9 more than 15.

The second sequence has the same pattern.

2007-09-06 16:48:36 · answer #2 · answered by Larry C 3 · 0 0

While most of the answers are correct, an easier expression for these sequences is squares minus 1.

-1 = 0^2 - 1
0 = 1^2 - 1
3 = 2^2 - 1
8 = 3^2 - 1
...

2007-09-06 16:49:24 · answer #3 · answered by thomasoa 5 · 0 0

A common gimmick in sequences is to have constant differences between terms, or constant differences between differences. That approach works for both of these; the second differences in the first one are all 2, so the next term is 24+11 = 35; and that is also true of the second one, so the next term is 35+13 = 48.

2007-09-06 16:45:43 · answer #4 · answered by Anonymous · 0 1

It looks like you keep on adding the next odd number (first you add 1, then 3, then 5, etc...),

The next number should be 35 + 13 = 48

2007-09-06 16:44:45 · answer #5 · answered by Christophe G 4 · 1 1

first sequence:
0²-1, 1²-1, 2²-1, ....
a[sub n] = (n-1)² - 1

second sequence is 1st offset by 1:
1²-1, 2²-1, ....
a[n] = n² - 1

2007-09-06 16:49:24 · answer #6 · answered by Philo 7 · 0 0

note, the second sequence is the first one started one term later.
The sequence is n^2-1, for n starting at 0 in the first, at 1 in the second series.

2007-09-06 16:48:31 · answer #7 · answered by holdm 7 · 1 1

every next number is sum of 4 +X
-1+4=3
3+4+1=8
8+4+2=15
Y(n)=Y(n-1)+3+n

2007-09-06 16:47:00 · answer #8 · answered by kkhorev 2 · 1 1

the they go up by odd #'s
(+1, +3, +5, +7, +9....)

2007-09-06 16:45:53 · answer #9 · answered by Bloody Hell 5 · 0 1

try multiplying, adding, dividing, and subtracting. it may be 2 diffferent ones like add 9 divide by 3 or something. i will take time.

2007-09-06 16:46:05 · answer #10 · answered by Amanda 1 · 0 1

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