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Exponential decaying substance decreases by 32% in 10 hours. What is the half life of the substance?

2007-09-06 09:35:55 · 2 answers · asked by TD 1 in Science & Mathematics Mathematics

2 answers

P=P_0 2^(-t/T)
where P_0 is the original amount and T is the half-life.

When t=10, you have P=(1-.32)P_0=.68P_0,
so
.68=2^(-10/T).
Now solve for T:
ln(.68)=(10/T)ln(2), so
T=-10*ln(2)/ln(.68)=18hrs.

2007-09-06 09:46:12 · answer #1 · answered by mathematician 7 · 0 0

0.68 = r^10 ......... amount remaining
0.50 = r^x

log (0.68) = 10 log r
log (0.50) = x log r

log (0.68) .. 10
------------- = --- ........ pretty proportion
log (0.50) ... x

x = 10 log (0.50) / log (0.68)
x = 17.97 hr

2007-09-06 16:46:04 · answer #2 · answered by Philo 7 · 0 0

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