1/4 [-5+5(-3)]
1/2[6-4^2]
2007-09-06 08:48:49 · 8 answers · asked by Mo 1 in Science & Mathematics ➔ Mathematics
Question 1
(1/4) (- 20) = - 5
Question 2
(1/2) (- 10) = - 5
2007-09-06 10:38:28 · answer #1 · answered by Como 7 · 1⤊ 0⤋
Remember order of operations: PEMDAS
Multiply inside the parenthesis first:
1/4 [(-5)+5(-3)]=1/4 [(-5)-15]=1/4 (-20)= -5
1/2 (6-4^2)=1/2 (6-16)=1/2 (-10)= -5
2007-09-06 15:57:12 · answer #2 · answered by misshiccups 3 · 0⤊ 0⤋
1/4 [-5+5(-3)] = 1/4 [ -5 - 15}
= (1/4) ( -20)
= - 5
1/2[6-4^2]
= (1/2) ( 6 - 16)
= (1/2) (-10)
= -5
2007-09-06 15:55:01 · answer #3 · answered by vlee1225 6 · 0⤊ 0⤋
1/4 [ -5 + 5 (-3)]= 1/4 [ -5 -15] =1/4 (-20) = -5
1/2 [ 6-4^2] = 1/2 [ 6 - 16] = 1/2 [-10] = -5
2007-09-06 15:54:02 · answer #4 · answered by Will 4 · 0⤊ 1⤋
1/4[-5+5(-3)]
(-5 -15) / 4
-20 / 4
-5
----------------------
1/2[6-4^2]
(6 - 4^2) / 2
(6 - 16) / 2
-10 / 2
-5
2007-09-06 15:57:56 · answer #5 · answered by Wile E. 7 · 0⤊ 0⤋
1/4[-5 + 5(-3)]
1/4[-5 - 15]
1/4[ -20] = -5
1/2[6 -4^2]
1/2[ 6 - 16]
1/2[-10] = -5
2007-09-06 15:53:19 · answer #6 · answered by lenpol7 7 · 0⤊ 1⤋
You need to understand the 'order of operations' when heading in to a problem like this. I like PEMDAS:
P - Parentheses
E - Exponents
M - Multiplication
D - Division
A - Addition
S - Subtraction
So, apply PEMDAS to your eqn:
1. (1/4)*(-5+5*(-3)) always do the innermost parenthese first:
(1/4)*(-5-15) = (1/4)*(-20) = -5
2. (1/2)*(6 - (4^2)) = (1/2)*(6-16) = (1/2)*(-10) = -5
2007-09-06 15:54:29 · answer #7 · answered by miggitymaggz 5 · 0⤊ 0⤋
1/4 [-5+5(-3)] =1/4(-5-15)=1/4(-20)=-5
-------------------------------
1/2[6-4^2]=1/2(6-16)=1/2(-10)=-5
2007-09-06 15:56:48 · answer #8 · answered by Anonymous · 0⤊ 0⤋