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A spherical balloon is being inflated and the radius of the balloon is increasing at a rate of 3 cm/s.

a)Express the radius r of the balloon as a function of the time t (in seconds). r(t)=?

b) If V is the volume of the balloon as a function of the radius, find V(r(t)).

2007-09-06 08:23:50 · 2 answers · asked by lady_divine@sbcglobal.net 1 in Science & Mathematics Mathematics

2 answers

dr/dt=3 so r=3t +ro where ro is the initial radius of the balloon.
Supposing that you started with ro=0
V=4/3*pi*(3t)^3=36*pi*t^3

2007-09-06 09:13:48 · answer #1 · answered by santmann2002 7 · 0 0

the adaptation in quantity is the quantity of air required to inflate the balloon from an already inflated state to an outstanding extra inflated state. quantity= ((4/3) pi(r+2)^3)-((4/3)pi(r)^3)

2016-12-16 13:08:42 · answer #2 · answered by Anonymous · 0 0

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