Organic Chem. Orbital Bonding Problem. please help!!!!?

Question

I am given a compound. It is C3H2F2.. with the 3 carbons being double bonded to each other. The questions wants me to indicate the type of orbitals on each atom used to form each bond. I am not sure if I am right but I know the first and third carbon use sp2 orbitals to bond to hydrogen (s orbital) and fluorine (which I am not sure what orbital it is to bond to carbon). the middle carbon uses sp orbitals. I'm really confused as to what orbitals fluorine uses to bond to carbon and if the rest of my work is correctly done? please help!!

Answer 1

What you say is correct. The structure is like this
H..................F
...\.............../
....C = C = C
.../...............\
H..................F
The middle carbon is sp hybridised to form a sigma bond to each neighbouring carbon. It uses its two remaining p-electrons to form pi bonds (at 90° to each other) to the end carbons.
The end carbons are sp2 hybridised to form sigma bonds to the terminal atoms and the middle carbon. They use their remaining p-electron to form a pi bond to the central carbon.
The terminal hydrogens use a s-electron to form a sigma bond to the end carbon.
The terminal fluorines are sp3 hybridised forming a sigma bond to the end carbon and leaving three lone pairs on the fluorine.

Answer 2

I believe you are correct. The F bonds to the C just like the H bonds to the C

Answer 3

React benzene with the two butyl anhydride (CH3CH2CH2C(=O)OC(=O)CH2CH2CH3) or butyryl chloride (CH3CH2CH2COCl) using AlCl3 ie the Friedel-Craft reaction. The fabricated from this may be a million-phenylbutan-a million-one. next cut back it using the Wolff-Kishner reaction. it somewhat is done decrease than hardship-unfastened situations and could not deliver approximately acid catalyzed rearrangements. The Clemmensen help is administered decrease than acidic situations and could deliver approximately rearrangements. i think the cycloheptatriene you describe is fragrant. i'm hoping this helps