Question 1
2 x ( x ² - 2 x - 15 )
2 x ( x - 5 ) ( x + 3 )
Question 2
2 ( x^4 - 3 x ² - 4 )
2( x ² - 4 ) ( x ² + 1 )
2 ( x - 2 ) ( x + 2 ) ( x ² + 1 )
2007-09-06 07:46:22
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answer #1
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answered by Como 7
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2x^3 - 4x^2 - 30x factor out 2x
2x (x^2 - 2x - 15) factor the poly
2x(x - 5)(x + 3) answer
2007-09-06 07:33:14
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answer #2
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answered by fivestring46 4
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answer to the first
2x^3-4x^2-30x
2x(x^2-2x-15)
2x(x-5)(x+3)
2007-09-06 07:16:02
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answer #3
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answered by Anonymous
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the finished factorization of right here polynomials are as follows: (a) 2a^2 - 4a - 2 = 2(a^2 - 2a - a million) observe that the polynomial expression a^2 - 2a - a million is already top, i.e., a^2 - 2a - a million isn't factorable, each time a is an integer. (b) t^2 - 9w^2 = (t - 3w)(t + 3w)
2016-11-14 08:43:23
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answer #4
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answered by tine 4
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2X(X-5)(X+3)
2(X-2)(X+2)(X^2+1)
2007-09-06 07:17:09
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answer #5
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answered by Mr. Smith 5
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2x(x^2-2x-15)=2x(x-5)(x+3)
2(x^4-3x^2-4)=2(x^2-4)(x^2+1)
=2(x+2)(x-2)(x^2+1)
2007-09-06 07:16:41
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answer #6
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answered by vmarsh3 2
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2X^3-4X^2-30X
=2x(x^2-2x-15)
=2x(x+3)(x-5)
2X^4-6X^2-8
=2(x^4-3x^2-4)
=2(x^2-4)(x^2+1)
=2(x-2)(x+2)(x^2+1)
2007-09-06 07:14:38
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answer #7
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answered by iyiogrenci 6
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