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2X^3-4X^2-30X




2X^4-6X^2-8

2007-09-06 07:05:13 · 7 answers · asked by gladdo19 1 in Science & Mathematics Mathematics

7 answers

Question 1
2 x ( x ² - 2 x - 15 )
2 x ( x - 5 ) ( x + 3 )

Question 2
2 ( x^4 - 3 x ² - 4 )
2( x ² - 4 ) ( x ² + 1 )
2 ( x - 2 ) ( x + 2 ) ( x ² + 1 )

2007-09-06 07:46:22 · answer #1 · answered by Como 7 · 1 0

2x^3 - 4x^2 - 30x factor out 2x
2x (x^2 - 2x - 15) factor the poly
2x(x - 5)(x + 3) answer

2007-09-06 07:33:14 · answer #2 · answered by fivestring46 4 · 0 0

answer to the first

2x^3-4x^2-30x
2x(x^2-2x-15)
2x(x-5)(x+3)

2007-09-06 07:16:02 · answer #3 · answered by Anonymous · 0 0

the finished factorization of right here polynomials are as follows: (a) 2a^2 - 4a - 2 = 2(a^2 - 2a - a million) observe that the polynomial expression a^2 - 2a - a million is already top, i.e., a^2 - 2a - a million isn't factorable, each time a is an integer. (b) t^2 - 9w^2 = (t - 3w)(t + 3w)

2016-11-14 08:43:23 · answer #4 · answered by tine 4 · 0 0

2X(X-5)(X+3)

2(X-2)(X+2)(X^2+1)

2007-09-06 07:17:09 · answer #5 · answered by Mr. Smith 5 · 0 0

2x(x^2-2x-15)=2x(x-5)(x+3)
2(x^4-3x^2-4)=2(x^2-4)(x^2+1)
=2(x+2)(x-2)(x^2+1)

2007-09-06 07:16:41 · answer #6 · answered by vmarsh3 2 · 0 0

2X^3-4X^2-30X
=2x(x^2-2x-15)
=2x(x+3)(x-5)





2X^4-6X^2-8
=2(x^4-3x^2-4)
=2(x^2-4)(x^2+1)
=2(x-2)(x+2)(x^2+1)

2007-09-06 07:14:38 · answer #7 · answered by iyiogrenci 6 · 0 0

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