how do you solve a quadratic formula question when there is no middle/b term?

Question

example= 9x^2=144

Answer 1

In that case, b=0.
You don't actually need the quadratic formula to solve this equation.

Rewrite the equation:
9x^2 - 144 = 0 (divide both sides by 9)
x^2 - 16 = 0
(x -4)(x+4) = 0
x = 4 or -4

If you really want to solve using the quadratic formula:
a = 1
b = 0
c = -16

(-0 +/- sqrt(0^2 - 4(1)(-16)))/2(1)
=(+/- sqrt(64))/2
=(+/- 8)/2
= +/- 4

Answer 2

Easy. 9x^2 = 144

x^2 = 144/9

x = + 12/3 = 4 or x = -4

If you must plug into ax^2 + bx + c = 0 formula, simply set b = 0

Answer 3

no formula needed:

x^2 = 144/9
X = Sqrt 144/9 = +/- 12/3 = +/- 4

Answer 4

9x^2 = 144

A quadratic equation has the form:

ax^2 + bx + c = 0 (a, b or c can be negative)

First, convert to quadratic form:
9x^2 + 0x - 144 = 0

The Quadratic Formula has the form:
x = (-b +/- SQRT((b^2) - 4ac)) / 2a

In this case, a = 9, b = 0, c = -144

x = (-0 +/- SQRT((0^2) - 4(9)(-144))) / 2(9)
x = +/- SQRT(-4(9)(-144))) / 18
x = +/- SQRT(-4(-1296)) / 18
x = +/1 SQRT(5184) / 18
x = +/- 72 / 18
x = +/- 4

You could just simply solve for x:

9x^2 = 144
x^2 = 144 / 9
x^2 = 16
x = SQRT(16)
x +/- 4

But you asked for a quadratic...

Answer 5

9x^2=144
x = +/- sqrt(144/9) = +/- 12/3 = +/- 4

Answer 6

9x^2 = 144
divide both sides by 9
x^2 = 16
x = +/- 4

Answer 7

ax^2 = c
x^2 = c/a
x = (c/a)^1/2 (with + and - sign)
eg 9x^2 = 144
x^2 = 144/9 = 16
x = +4, -4

Answer 8

There actually is a middle term...it just happens to have a coefficient of 0. You can still solve it the same way, though.

Answer 9

x ² = 16
x = ± 4

Answer 10

Well there is in a way a b term it is just 0b which is just 0 so they don't put it in. so one you solve just use 0 for b and you will get your answer.