2007-09-06 06:29:50 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
-3y^3(y-7)
=-3y^4+21y^3
2007-09-06 06:37:50 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Simplify:
= - 3y^3(y - 7)
= - 3y^4 + 21y^3
2007-09-10 07:44:05 · answer #2 · answered by Jun Agruda 7 · 3⤊ 0⤋
-3y^3(y-7)=x
-3y^3=x/(y-7)
that is as bout as far as u can take it with out what the x stands for or with out the # for y
2007-09-06 13:39:16 · answer #3 · answered by jer r 2 · 0⤊ 0⤋
-3y^3(y-7) = -3y^4 +21y^3
2007-09-06 13:39:06 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
- 3 y^4 + 21 y ³
2007-09-06 15:26:19 · answer #5 · answered by Como 7 · 2⤊ 0⤋
I'm sure you mean: -3y^3*(y-7)=0.
The answers are y=(0, 0, 0 and 7).
2007-09-06 13:38:18 · answer #6 · answered by Scott 3 · 0⤊ 0⤋
-3y^3(y-7)
=-3y^4+21y^3 ans
2007-09-06 13:42:18 · answer #7 · answered by MAHAANIM07 4 · 0⤊ 0⤋