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Huge icebergs can be seen only in small visible fraction. If the specific gravity of seawater and ice are 1.024 and .817, respectively, what is this fraction?

2007-09-06 06:29:22 · 2 answers · asked by physics maniac 2 in Science & Mathematics Physics

2 answers

It varies.

"The density of seawater at the surface of the ocean varies from 1,020 to 1,029 kilograms per cubic meter."


"Seawater is usually some 3.5 percent heavier than fresh water because it contains about 35 pounds of salts in each 1,000 pounds of water"

It is customary to report the density os seawater in equivalent to "grams per litre excess over one kilogram,"designated by the symbol σ. In this notation, the specific gravity of 1.025 is expressed as σ of 25."

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2007-09-06 06:39:56 · answer #1 · answered by Anonymous · 0 1

If the specific gravity of ice is 0.817 and the specific gravity of seawater is 1.024, then it only requires 0.817/1.024 = 0.798 of the volume of the iceberg to be submerged in seawater, because the submerged ice will displace seawater with a weight equal to the weight of the entire iceberg, and buoyancy will keep the iceberg afloat. If 0.798 of the iceberg is submerged, then 1 - 0.798 = 0.202 of the iceberg can be seen.

2007-09-10 05:17:31 · answer #2 · answered by DavidK93 7 · 0 0

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