the expression x4+x3=2mx2-14m4 leaves a remainder of 32 when divided by x+2m. Find he possible values of m.?

Question

x4 is x to the 4th power, x3 is x to the 3rd power, -14m4 is -14m to the 4th power...it's under the topic remainder theorem

Answer 1

x4+x3=2mx2-14m4
x4+x3-2mx2+14m4=0
let f(X)= x4+x3-2mx2+14m4
f(-2m)=(-2m)^4 + (-2m)^3 - 2m(-2m)^2 + 12 m^4=32
16m^4-8m^3-8m^3+12m^4=32
28m^4-16m^3=32
7m^4- 4m^3=8
m^3(7m-4)=8
m^3 = 8 or 7m-4=8
m=2 or 7m=12
m=12/7

Answer 2

Are you sure that expression had an = sign ?

Answer 3

Do your own homework!