English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

53 48 17 71 81 97 96 87 84 101 please help me!

2007-09-06 01:23:21 · 2 answers · asked by Isabelle Claire L 1 in Science & Mathematics Mathematics

2 answers

All the even numbers in your list are composite.
So 48,96 and 84 are all composite.
Now look at 81 and 87. If you add the digits
in each case you get a number that's a multiple of 3.
So both of these are divisible by 3 and are composite.
That leaves 53,17,71, 97 and 101.
Let's test each for primality.
There's a simple rule for this.
A number n is prime if it has no prime factors
less than its square root.
The square roots of all 5 numbers above are
less than 11 because 11² = 121.
So we only need test for divisibility by 2,3,5 and 7.
Since none of the 5 are divisible by any of these
they are all prime.
Hope that helps!

2007-09-06 03:27:36 · answer #1 · answered by steiner1745 7 · 0 0

Answers:
53 = prime
48 = 2^4 * 3
17= prime
71 = prime
81 = 3^4
97 = prime
87 = 3 * 29
84 = 2^2 * 3 * 7
101 = prime

2007-09-06 08:33:20 · answer #2 · answered by Jun Agruda 7 · 3 0

fedest.com, questions and answers