Vec A = (1.28,2.26) Vec B (4.24,-3.72) Find the components of B-A.?

Question

For some reason when I switch signs, the answer is still incorrect. Math error? Also Find CCW Angle that b-a makes on positive x-axis?

... I've done the calculation for this as well.. for some reason it's still off by an "additive constant" ..

Answer 1

B - A = (2.96, -5.98)
Magnitude = 6.6725
Angle = arctan(-5.98/2.96) = -1.1112 rad = -63.665 deg
This angle, being negative, represents clockwise rotation from the x axis. The B - A vector is in the 4th (lower right) quadrant. It shouldn't be hard to visualize. From (0,0), you go right 2.96 on the x axis, then down 5.98 parallel to the y axis. The line drawn from (0,0) to this point makes an angle greater than 45 deg with the x axis, since 5.98>2.96. In interval form, the angle covers the interval 0 to -63.665 deg.
EDIT: What's the additive constant? Maybe 360 deg added to the angle? From your other question it seems they require a positive angle and perhaps are rounding the result. If so, the answer is 360-63.665=296.335 deg or 296 deg rounded.