English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

2007-09-05 19:31:59 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

Its half the value of e^ square root x

2007-09-05 19:36:20 · answer #1 · answered by 222 3 · 0 1

derivative of e^ square root x =
[derivative of (e^ square root x) wrt square root of x]
*[derivative of square root of x with respect to x] =
[(e^ square root x)]*[1/(2(square root of x))]

2007-09-05 19:41:13 · answer #2 · answered by Debidas M 2 · 0 0

Let sqrt x be denoted by u.

d/dx (e^u)= du/dx(e^u)
therefore
e^sqrt x = [d/dx(sqrt x)] (e^ sqrt x)
= sqrt x/ 2x (e^sqrt x)

2007-09-05 20:44:49 · answer #3 · answered by polarbear 1 · 0 0

y = e^√x Remember d/dx e^u = e^u d/dx(u) so
dy/dx = (e^√x)/(2√x)

HTH

Doug

2007-09-05 19:43:25 · answer #4 · answered by doug_donaghue 7 · 0 0

fedest.com, questions and answers