Math Question!!!?

Question

Find the standard form of the equation of the circle having the following properties:

Center at the origin
Containing the point (-4,1)

Answer 1

given the point (-4,1) we have a radius of sqrt(17).

therefore:

(x+0)^2 + (y + 0) ^2 = 17

if it were not centered at origin and centered at (a,b) you would get:

(x - a)^2 + (y - b) ^2 = r^2

Answer 2

Since it is centered at the origin, we just need to find the radius.

Since (-4,1) is on the circle, the radius is the length from the origin to this point.

r^2 = (-4)^2 + 1^2 = 17


So the equation is x^2 + y^2 = 17


x^2 + y^2 = 17

Answer 3

x²+y²=r²
is the standard equation for a circle whose center is at the origin having a radius r.

since you are given an x & y point you just plug it in and solve to find r.

(-4)²+(1)²=r²

r² = 17
r = √17

Equation for this circle becomes:
x²+y²=17

Answer 4

for cicle with centre at origin
x^2+y^2=r^2

put x=-4 & y=1

u get
x^2+y^2=17

Answer 5

wow thanks for ur rude answer =D